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The HCF of 12576 and 4052 is:

A4
B8
C6
D2
Answer & Solution
Correct answer: A. 4
1. Successive remainders are 420, 272, 148, 124, 24 and 4. 2. The remainder then becomes zero. 3. So the HCF is 4. _Source: syllabus Mathematics, Chapter 1, Real Numbers._
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