In Young's double slit experiment, fringe width:
AD/d
Bλ d / D
Cλ D / d (where d = slit separation, D = screen distance)
Dλ D × d
Answer & Solution
Correct answer: C. λ D / d (where d = slit separation, D = screen distance)
β = λD/d. Distance between consecutive bright (or dark) fringes. Wider for longer wavelength or larger D, narrower for larger d. (Wave optics, but appears in JEE Main syllabus.)
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