For total internal reflection at glass-water interface (n_g = 1.5, n_w…

Question

For total internal reflection at glass-water interface (n_g = 1.5, n_w = 1.33), critical angle:

Accepted Answer

D. sin⁻¹(1.33/1.5) ≈ 62.5°

sin θ_c = n_rare/n_dense = 1.33/1.5 ≈ 0.887. θ_c ≈ 62.5°.
Larger than glass-air case (≈42°) because the n-ratio is smaller.

Answer

48.6°

Answer

sin⁻¹(1.5/1.33)

Answer

30°

For total internal reflection at glass-water interface (n_g = 1.5, n_w = 1.33), critical angle: