Practice free →
HomeJEE MainPhysicsRay Optics › A coin at the bottom of a 0.5 m water tank (n = …

A coin at the bottom of a 0.5 m water tank (n = 4/3) appears at depth:

A0.667 m
B0.25 m
C0.375 m (= 0.5 × 3/4)
D0.5 m
Answer & Solution
Correct answer: C. 0.375 m (= 0.5 × 3/4)
Apparent depth = 0.5 / (4/3) = 0.5 × 3/4 = 0.375 m. Coin appears about 12.5 cm shallower than reality. Use this to estimate how to grab objects underwater.
Solve this in the app — JEE Main practice & 24k+ MCQs →
Related questions