For complex reaction with rate-determining step that involves 2 molecules of A, the order in A is:
A2
BSame as molecularity of the rate-determining step (here: 2)
CAlways 1
DCannot determine
Answer & Solution
Correct answer: B. Same as molecularity of the rate-determining step (here: 2)
For complex reactions, observed rate law reflects the slow (rate-determining) elementary step's molecularity in each reactant. So if RDS has 2 A's, observed order is 2 in A.
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