Find (1 + i)²:
A2i
B2
C-2i
D0
Answer & Solution
Correct answer: A. 2i
(1+i)² = 1 + 2i + i² = 1 + 2i - 1 = 2i.
Related questions
The number of distinct $n$th roots of a non-zero complex number is:Using De Moivre's theorem, $(\cos\theta + i in\theta)^4$ equals:The modulus of $z = 5 + 12i$ is:The conjugate of $z = 3 - 4i$ is:Find (3 + 4i)/(1 + 2i):If z1, z2, z3 are vertices of an equilateral triangle, then:Solve: z² + z + 1 = 0:For roots of unity ω^n = 1: which is the SMALLEST n such that 1 + ω + ω² + ... + ω^(n-1) =