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The multiplicative inverse of z = 2 - 3i is:

A1/(2 - 3i)
B2 + 3i
C(2/13) + (3/13)i
D(2 + 3i)/(2 - 3i)
Answer & Solution
Correct answer: C. (2/13) + (3/13)i
z⁻¹ = z̄ / |z|². z̄ = 2 + 3i; |z|² = 4 + 9 = 13. So z⁻¹ = (2 + 3i)/13 = 2/13 + (3/13)i.
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