In a meter bridge experiment, when wavelength changes from 600 nm to 400 nm, the fringe width:
ADecreases by factor 600/400
BIncreases
CStays same
DDecreases by factor 400/600
Answer & Solution
Correct answer: D. Decreases by factor 400/600
β = λD/d. β2/β1 = λ2/λ1 = 400/600 = 2/3. So β decreases by factor 2/3 (= 400/600).
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