Solubility of CaF2 in water (Ksp = 4.0 × 10⁻¹¹):
A10⁻⁶ M
B10⁻³ M
C4 × 10⁻¹¹ M
D2.15 × 10⁻⁴ M
Answer & Solution
Correct answer: D. 2.15 × 10⁻⁴ M
CaF2 ⇌ Ca²+ + 2F-. If s is solubility, [Ca²+] = s and [F-] = 2s. Ksp = s(2s)² = 4s³. So s = (Ksp/4)^(1/3) = (10⁻¹¹)^(1/3) ≈ 2.15 × 10⁻⁴ M.
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