Solubility product Ksp of AgCl is 1.6 × 10⁻¹⁰. Its solubility in pure water (mol/L):
A8 × 10⁻¹⁰
B1.26 × 10⁻⁵
C1.6 × 10⁻⁵
D1.6 × 10⁻¹⁰
Answer & Solution
Correct answer: B. 1.26 × 10⁻⁵
AgCl ⇌ Ag+ + Cl-. If solubility = s, then [Ag+][Cl-] = s² = Ksp. s = √(1.6 × 10⁻¹⁰) = 1.26 × 10⁻⁵ mol/L.
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