pOH of a solution with pH = 8.5 (at 25°C):
A9.5
B8.5
C6.5
D5.5
Answer & Solution
Correct answer: D. 5.5
At 25°C, pH + pOH = 14. So pOH = 14 - 8.5 = 5.5. Solution is mildly basic (pH > 7).
Keep practising Unit 7A1: Equilibrium Constant and Dynamic Equilibrium
Browse all Unit 7A1: Equilibrium Constant and Dynamic Equilibrium questions for JEE Advanced, or explore more Chemistry topics.
Related questions
Degree of dissociation α of weak acid HA (Ka = 1.8 × 10⁻⁵) in 0.01 M solution:For the reaction H2(g) + I2(g) ⇌ 2HI(g) with Kc = 50 at 800 K, if [H2] = [I2] = 0.01 M iniIn a saturated solution of AgCl, [Ag+] = 1.26 × 10⁻⁵. If KNO3 is added (no common ion), soAt equilibrium, the ratio of forward to reverse reaction rates:At 298 K, water has Kw = 10⁻¹⁴. Concentration of H+ in pure water:If K = 1 for a reaction, the standard free energy change ΔG°:For the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), at equilibrium increasing pressure:For the reaction PCl5(g) ⇌ PCl3(g) + Cl2(g), if initial pressure of PCl5 is P0 and degree