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Bond order from MOT (molecular orbital theory):

A= 1 always
B= number of bonds
C= (bonding electrons - antibonding electrons) / 2
D= 0 always
Answer & Solution
Correct answer: C. = (bonding electrons - antibonding electrons) / 2
**In MOT:** BO = (N_bonding - N_antibonding)/2. Half-integer values are possible! **Example:** O₂ has BO = 2 (8 bonding - 4 antibonding)/2 = 2.
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