A charged particle q is held at rest in vertical equilibrium in a uniform electric field E pointing upward. Charge-to-mass ratio q/m:
Ag/E
BE/g
CgE
DΕ/g²
Answer & Solution
Correct answer: A. g/E
**For equilibrium:** qE = mg (electric force up = gravity down).
**So q/m = g/E. The particle is essentially 'levitated' by the field.**
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