alleryFor a spherical conductor of radius R carrying charge Q, the potential AT THE SURFACE equals:
A0
BkQ/R²
CkQ/R
D2kQ/R
Answer & Solution
Correct answer: C. kQ/R
V_surface = kQ/R. Same as the field at the surface times R. Note: potential INSIDE a conductor is uniform = surface value; field inside = 0.
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