Capacitance changes when DIELECTRIC of relative permittivity K is inserted:
ADecreases by K
BStays same
CIncreases by factor K (C → KC)
DBecomes zero
Answer & Solution
Correct answer: C. Increases by factor K (C → KC)
**With dielectric:** C = Kε₀A/d.
Capacitance becomes K times the vacuum value.
Energy stored at same voltage also increases (since U = ½CV²).
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