alleryFor a parallel plate capacitor with plate area A and separation d, the capacitance in vacuum:
AC = ε₀A/d
BC = ε₀d/A
CC = A/(ε₀d)
DC = dε₀A
Answer & Solution
Correct answer: A. C = ε₀A/d
C = ε₀A/d.
Larger area or smaller separation → more capacitance.
Insertion of dielectric multiplies capacitance by relative permittivity ε_r.
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