alleryThe radius of circular motion of a particle of charge q, mass m, speed v in field B (perpendicular) is:
AqB/(mv)
Bmv/(qB)
CmvB/q
Dv/(qBm)
Answer & Solution
Correct answer: B. mv/(qB)
qvB = mv²/r ⇒ r = mv/(qB).
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