For what value of x does f(x) = 2x² - 8x reach its minimum?
Ax = 1
Bx = 2
Cx = 4
Dx = -4
Answer & Solution
Correct answer: B. x = 2
Minimum of parabola at x = -b/(2a) = -(-8)/(2(2)) = 8/4 = 2.
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