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Which expression is equivalent to $\frac{2}{x+1} - \frac{1}{x-2}$?

A$\frac{x - 5}{(x+1)(x-2)}$
B$\frac{1}{(x+1)(x-2)}$
C$\frac{3}{(x+1)(x-2)}$
D$\frac{x+5}{(x+1)(x-2)}$
Answer & Solution
Correct answer: A. $\frac{x - 5}{(x+1)(x-2)}$
Common denominator $(x+1)(x-2)$: $\frac{2(x-2)}{(x+1)(x-2)} - \frac{x+1}{(x+1)(x-2)} = \frac{2x - 4 - x - 1}{(x+1)(x-2)} = \frac{x - 5}{(x+1)(x-2)}$.
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