For what value of k will the system 2x + 3y = 6 and 4x + ky = 8 have NO solution?
Ak = 3
Bk = 4
Ck = 6
Dk = 8
Answer & Solution
Correct answer: C. k = 6
For no solution: a₁/a₂ = b₁/b₂ ≠ c₁/c₂. So 2/4 = 3/k requires k = 6, AND 6/8 ≠ 1/2 (i.e., 3/4 ≠ 1/2 — true). So at k = 6 the lines are parallel but distinct: no solution.
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