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A polynomial with real coefficients has 2 plus 3i as a zero, so it must also have as a zero:
A3 minus 2i
B2 plus 3i
C3 plus 2i
D2 minus 3i
Answer & Solution
Correct answer: D. 2 minus 3i
1. Complex zeros of a real polynomial arrive in pairs.
2. The partner is the conjugate of the one already known.
3. So 2 minus 3i is also a zero.
_Source: OpenStax Precalculus 2e, Chapter 3, Polynomial and Rational Functions._
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