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A charge of 10 nC flows through a circuit in 3.0 x 10^-6 s. What is the current during this time?
A3.3 mA
B30 mA
C0.33 mA
D33 mA
Answer & Solution
Correct answer: A. 3.3 mA
1. Current is charge divided by time: I = deltaQ / deltat.
2. Substitute deltaQ = 10 x 10^-9 C and deltat = 3.0 x 10^-6 s.
3. I = (10 x 10^-9 C) / (3.0 x 10^-6 s) = 3.3 x 10^-3 A = 3.3 mA.
_Source: OpenStax Physics (CC BY 4.0), Ch 19 "Electrical Circuits", section Direct and Alternating Current_
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