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A circuit has 0.12 A flowing through it across a potential drop of 3.0 V. What power is dissipated?
A3.6 watt
B0.36 watt
C25 watt
D0.036 watt
Answer & Solution
Correct answer: B. 0.36 watt
1. Electric power is P = IV.
2. Substitute I = 0.12 A and V = 3.0 V.
3. P = (0.12 A)(3.0 V) = 0.36 W.
_Source: OpenStax Physics (CC BY 4.0), Ch 19 "Electrical Circuits", section 19.4 Electric Power_
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