If 3.0 kJ of heat is added to 1.0 kg of water at room temperature, what is the resulting temperature change? Use c(water) = 4186 J per kg per degree C.
A0.36 degrees C
B0.72 degrees C
C3.6 degrees C
D7.2 degrees C
Answer & Solution
Correct answer: B. 0.72 degrees C
1. Rearranging Q = mcΔT for temperature change gives ΔT = Q divided by (mc).
2. Substitute Q = 3000 J, m = 1.0 kg, and c = 4186.
3. Dividing gives ΔT = 0.72 degrees C.
4. 0.36 degrees C would result from using twice the correct specific heat.
5. 3.6 and 7.2 degrees C are ten times too large.
6. So 0.72 degrees C is correct.
_Source: OpenStax Physics (CC BY 4.0), Ch 11 "Thermal Energy, Heat, and Work", section 11.2 Heat, Specific Heat, and Heat Transfer_
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