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If 2500 kJ of heat is just enough to melt 3.0 kg of an unknown substance, what is that substance's latent heat of fusion?

A280 kJ/kg
B570 kJ/kg
C830 kJ/kg
D7500 kJ/kg
Answer & Solution
Correct answer: C. 830 kJ/kg
1. Rearranging Q = mLf for the latent heat of fusion gives Lf = Q divided by m. 2. Substitute Q = 2500 kJ and m = 3.0 kg. 3. Dividing gives Lf = 833 kJ/kg, which rounds to 830 kJ/kg. 4. 7500 kJ/kg would result from multiplying instead of dividing. 5. 280 and 570 kJ/kg do not come from this data at all. 6. So 830 kJ/kg is correct. _Source: OpenStax Physics (CC BY 4.0), Ch 11 "Thermal Energy, Heat, and Work", section 11.3 Phase Change and Latent Heat_
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