In the sequence a_1 = 3, a_n = 3a_{n−1} + 2 (n>1), the value of a_3 is:
A35
B33
C29
D41
Answer & Solution
Correct answer: A. 35
a_2 = 3·3+2 = 11; a_3 = 3·11+2 = 35.
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