The Arithmetic Mean (AM) of two positive numbers $a$ and $b$ is
A$\sqrt{ab}$
B$2ab/(a+b)$
C$ab/(a-b)$
D$(a + b)/2$
Answer & Solution
Correct answer: D. $(a + b)/2$
1. Your syllabus: the Arithmetic Mean of $a$ and $b$ is half their sum.
2. $\text{AM} = \dfrac{a + b}{2}$.
3. Geometric interpretation: AM is the AVERAGE of two values — what you intuitively call the midpoint on a number line.
4. Option A is the Geometric Mean (GM). Option C is the Harmonic Mean (HM). Option D has no standard mean interpretation.
5. By the AM-GM inequality: $\text{AM} \geq \text{GM}$ with equality iff $a = b$. So AM is always the largest of the three classical means.
_Source: syllabus Mathematics, Ch 8, §8.4 (Arithmetic Mean), p. 9._
Keep practising Sequences and Series
Browse all Sequences and Series questions for AP Intermediate 1st Year, or explore more Mathematics topics.
Related questions
Sum of the CUBES of the first $n$ natural numbers, $1^3 + 2^3 + \ldots + n^3$, equalsSum of the SQUARES of the first $n$ natural numbers, $1^2 + 2^2 + 3^2 + \ldots + n^2$, equSum of the first $n$ natural numbers, $1 + 2 + 3 + \ldots + n$, equalsThe Geometric Mean (GM) of $4$ and $9$ isThe sum to INFINITY of the GP $1 + 1/2 + 1/4 + 1/8 + \ldots$ isThe sum of the first $n$ terms of a GP with first term $a$ and common ratio $r \neq 1$ isThe $n^\text{th}$ term of a Geometric Progression (GP) with first term $a$ and common ratiThe 10th term of an AP with first term $a = 5$ and common difference $d = 3$ is