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Hydrogen peroxide decomposes by a first order path with a half-life of 2.16 x 10^4 s. What is the rate constant?

A3.21 x 10^-4 per second
B1.50 x 10^-5 per second
C6.42 x 10^-5 per second
D3.21 x 10^-5 per second
Answer & Solution
Correct answer: D. 3.21 x 10^-5 per second
1. For a first order reaction t(1/2) = 0.693/k. 2. Rearranging gives k = 0.693 divided by t(1/2). 3. So k = 0.693 divided by 2.16 x 10^4 s. 4. That works out to 3.21 x 10^-5 per second. 5. The value 3.21 x 10^-4 per second is the same figure with the power of ten slipped by one. _Source: OpenStax Chemistry (CC BY 4.0), Ch 12 "Kinetics", section 12.4 Integrated Rate Laws_
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