Hydrogen peroxide decomposes by a first order path with a half-life of 2.16 x 10^4 s. What is the rate constant?
A3.21 x 10^-4 per second
B1.50 x 10^-5 per second
C6.42 x 10^-5 per second
D3.21 x 10^-5 per second
Answer & Solution
Correct answer: D. 3.21 x 10^-5 per second
1. For a first order reaction t(1/2) = 0.693/k.
2. Rearranging gives k = 0.693 divided by t(1/2).
3. So k = 0.693 divided by 2.16 x 10^4 s.
4. That works out to 3.21 x 10^-5 per second.
5. The value 3.21 x 10^-4 per second is the same figure with the power of ten slipped by one.
_Source: OpenStax Chemistry (CC BY 4.0), Ch 12 "Kinetics", section 12.4 Integrated Rate Laws_
Keep practising Kinetics
Browse all Kinetics questions for IMU CET, or explore more Chemistry topics.
Related questions
Which enzyme deficiency is described as the most common one in humans?Why are most catalytic converters preheated by an electric heater?Which catalyst coats the surface of most modern three way catalytic converters?Which international treaty began phasing out chemicals linked to ozone destruction?Which prize did Paul Crutzen, Mario Molina and Sherwood Rowland share for their work on ozNitric oxide takes part in the decomposition of ozone. Why is it called a catalyst?On a reaction diagram the reagents sit at 6 kJ and the transition state at 20 kJ. What is What effect does a catalyst have on the position of an equilibrium?