For 2NH3 giving N2 plus 3H2, how does the rate of formation of hydrogen compare with the rate of formation of nitrogen?
AIt is one third as fast
BIt is exactly the same
CIt is twice as fast
DIt is three times as fast
Answer & Solution
Correct answer: D. It is three times as fast
1. The balanced equation makes 3 mol of H2 for every 1 mol of N2.
2. Both are formed during the same stretch of time.
3. So hydrogen appears three times faster than nitrogen.
4. One third as fast inverts the stoichiometric ratio, which is the usual slip here.
5. Equal rates would need equal coefficients, which this equation does not have.
_Source: OpenStax Chemistry (CC BY 4.0), Ch 12 "Kinetics", section 12.1 Chemical Reaction Rates_
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