Propane burns as C3H8 + 5 O2 gives 3 CO2 + 4 H2O. What volume of oxygen at the same conditions reacts with 2.7 L of propane?
A5.4 L of oxygen
B13.5 L of oxygen
C8.1 L of oxygen
D0.54 L of oxygen
Answer & Solution
Correct answer: B. 13.5 L of oxygen
1. Both gases are measured at the same temperature and pressure, so volumes stand in for moles.
2. The balanced equation shows one propane to five oxygen.
3. So one volume of propane needs five volumes of oxygen.
4. Multiply: 2.7 L x 5 = 13.5 L of oxygen.
5. The coefficient 3 belongs to carbon dioxide, so answering 8.1 L means reading the product side by mistake.
6. No ideal gas calculation is needed here, because the shared conditions cancel out of the ratio.
_Source: OpenStax Chemistry (CC BY 4.0), Ch 9 "Gases", section 9.3 Stoichiometry of Gaseous Substances, Mixtures, and Reactions_
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