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Which expression gives the density of an ideal gas of molar mass M?

ADensity equals RT divided by PM
BDensity equals PM divided by RT
CDensity equals PR divided by MT
DDensity equals MT divided by PR
Answer & Solution
Correct answer: B. Density equals PM divided by RT
1. Start from PV = nRT and rearrange to n over V equals P over RT. 2. Multiply both sides by the molar mass M, which turns moles into grams. 3. Mass over volume is the density, so density equals P times M divided by R times T. 4. The formula behaves sensibly: raising the pressure packs more gas into a litre and raises the density, while heating it thins the gas out. _Source: OpenStax Chemistry (CC BY 4.0), Ch 9 "Gases", section 9.3 Stoichiometry of Gaseous Substances, Mixtures, and Reactions_
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