alleryStart learning →A 13.2 L scuba tank holds air at 153 atm and 27 degrees C. What volume does this air occupy in the lungs at 3.13 atm and 37 degrees C?
A645 L
B667 L
C624 L
D700 L
Answer & Solution
Correct answer: B. 667 L
1. Pressure, volume and temperature all change while the amount of air stays the same, so use the combined gas law.
2. Convert the tank temperature to kelvin: 27 + 273 = 300 K.
3. Convert the body temperature to kelvin: 37 + 273 = 310 K.
4. Write P1V1 over T1 equals P2V2 over T2: 153 x 13.2 / 300 = 3.13 x V2 / 310.
5. The left side is 2019.6 / 300 = 6.732 atm L per K.
6. Multiply by 310 K: 6.732 x 310 = 2086.9 atm L.
7. Divide by 3.13 atm: V2 = 667 L.
8. Ignoring the temperature change and using Boyle's law alone gives 645 L, which is the near miss set as a distractor.
_Source: OpenStax Chemistry (CC BY 4.0), Ch 9 "Gases", section 9.2 Relating Pressure, Volume, Amount, and Temperature: The Ideal Gas Law_
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