alleryStart learning →Which relation holds for a fixed number of moles of an ideal gas under two sets of conditions?
AP1V1/T1 equals P2V2/T2
BP1T1/V1 equals P2T2/V2
CV1T1/P1 equals V2T2/P2
DP1V1T1 equals P2V2T2
Answer & Solution
Correct answer: A. P1V1/T1 equals P2V2/T2
1. Start from PV = nRT and divide both sides by T, giving PV over T equals nR.
2. If the number of moles does not change, then n times R is the same before and after.
3. So P1V1 over T1 equals P2V2 over T2, which is the combined gas law.
4. The temperature sits in the denominator, so any option that multiplies by T instead has the relationship upside down.
5. Use atmospheres, litres and kelvin throughout for the units to stay consistent.
_Source: OpenStax Chemistry (CC BY 4.0), Ch 9 "Gases", section 9.2 Relating Pressure, Volume, Amount, and Temperature: The Ideal Gas Law_
Keep practising Gases
Browse all Gases questions for IMU CET, or explore more Chemistry topics.
Related questions
The van der Waals equation reduces to PV = nRT under which condition?A 4.25 L flask holds 3.46 mol of carbon dioxide at 229 degrees C. What pressure does the iIn the van der Waals equation, what does the constant b account for?Who developed the first and simplest equation that improves on the ideal gas law?Under which conditions does a real gas behave most nearly like an ideal gas?For a gas showing perfectly ideal behaviour, the compressibility factor Z takes which valuKinetic molecular theory explains Boyle's law by which change when the volume of a gas decAt a fixed temperature, how do lighter gas molecules compare with heavier ones?