alleryStart learning →A solenoid has n turns per unit length and carries current I. What is the field strength inside it?
AB = n I / mu0
BB = mu0 n / I
CB = mu0 n I
DB = mu0 I / n
Answer & Solution
Correct answer: C. B = mu0 n I
1. Inside a solenoid the field strength is B = mu0 n I.
2. Here n is the number of loops per unit length, found as N divided by the length.
3. The radius of the solenoid does not appear, unlike the single-loop result.
4. B is the field anywhere in the uniform interior region, not only at the centre.
5. Dividing by n instead of multiplying would mean a tightly wound coil gave a weaker field, which is wrong.
_Source: OpenStax College Physics (CC BY 4.0), Ch 22 "Magnetism", section 22.9 Magnetic Fields Produced by Currents: Ampere's Law_
Keep practising Magnetism
Browse all Magnetism questions for B.Tech EEE, or explore more Electrical Engineering topics.
Related questions
For which task are x ray images more effective than MRI images?Which sensor, operating at liquid helium temperature, can measure fields thousands of timeWhat is a recording of the magnetic field of the beating heart called?What does functional MRI actually detect when it maps activity in the brain?Nuclear magnetic resonance was formulated in 1946. Who received the 1952 Nobel Prize in PhWhat is the largest part of an MRI unit, and what field strength does it typically produceHow is the electron beam of a cathode ray tube aimed at a chosen point on the screen?Wires of infinite length cannot be built. How is the definition of the ampere realised in