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A current of 8.0 A flows into a junction, and 3.0 A leaves along one of the two branches. What current leaves along the other?

A8.0 A
B5.0 A
C3.0 A
D11.0 A
Answer & Solution
Correct answer: B. 5.0 A
1. The junction rule says the current entering a junction equals the current leaving it. 2. Here 8.0 A enters and one branch carries away 3.0 A. 3. The remaining branch must carry 8.0 A minus 3.0 A = 5.0 A. 4. This is conservation of charge at work, since charge cannot pile up at a junction. _Source: OpenStax College Physics (CC BY 4.0), Ch 21 "Circuits and DC Instruments", section 21.3 Kirchhoff's Rules_
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