Home › Karnataka SSLC (Class 10) › Mathematics › Polynomials › The zeroes of the polynomial $x^2 - 5x + 6$ are
The zeroes of the polynomial $x^2 - 5x + 6$ are
A-2 and -3
B1 and 6
C2 and 3
D2 and -3
Answer & Solution
Correct answer: C. 2 and 3
1. Factorise: $x^2-5x+6 = (x-2)(x-3)$.
2. Setting each factor to 0 gives $x=2$ and $x=3$.
3. Check: sum $=5=-(-5)/1$, product $=6=6/1$.
_Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch9 'Polynomials', §9.3_
Related questions
The polynomial 2x^3 minus 3x^2 plus x minus 5 is divided by x minus 2. What is the remaindWhat is the first step when factorising a cubic polynomial by hand?What is meant by the degree of a polynomial in one variable?Which condition must every exponent in a polynomial satisfy?The number of zeroes of the polynomial whose graph meets the x-axis at exactly two points The product of the zeroes of the polynomial $3x^2 - x - 6$ isA quadratic polynomial whose zeroes are 2 and 3 isThe sum of the zeroes of the polynomial $2x^2 - 8x + 6$ is