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For the quadratic polynomial $ax^2+bx+c$, the sum of its zeroes is
A$-\dfrac{b}{a}$
B$\dfrac{c}{a}$
C$\dfrac{b}{a}$
D$-\dfrac{c}{a}$
Answer & Solution
Correct answer: A. $-\dfrac{b}{a}$
1. If the zeroes are $\alpha$ and $\beta$, then $\alpha+\beta = -\dfrac{b}{a}$.
2. (The product $\alpha\beta = \dfrac{c}{a}$.)
3. So the sum of the zeroes is $-\dfrac{b}{a}$.
_Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch9 'Polynomials', §9.3_
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