alleryThe de Broglie wavelength associated with a particle of mass m and velocity v is
Aλ = m v / h
Bλ = h / (m v)
Cλ = h v / m
Dλ = h m v
Answer & Solution
Correct answer: B. λ = h / (m v)
1. de Broglie (1924) postulated wave-particle duality for matter.
2. Momentum p = m v; associated wavelength λ = h / p = h / (m v).
3. Confirmed for electrons by Davisson-Germer diffraction experiment.
4. h/(m v) is negligible for macroscopic objects but significant for electrons.
_Source: syllabus Chemistry, Ch 2 "Structure of Atom", §2.6_
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