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Heisenberg's uncertainty principle states

AΔE × Δt = h always
BΔx × Δp = 0 for microscopic particles
CΔx × Δp ≥ h/(2π), sometimes written as h/4π
DΔx and Δp can be measured with arbitrary precision
Answer & Solution
Correct answer: C. Δx × Δp ≥ h/(2π), sometimes written as h/4π
1. Simultaneous precise measurement of conjugate variables is impossible. 2. For position and momentum: Δx × Δp ≥ h/(4π) (equivalently ℏ/2). 3. The more precisely x is known, the less precisely p can be, and vice versa. 4. This is a fundamental limit, not an instrumental error. _Source: syllabus Chemistry, Ch 2 "Structure of Atom", §2.6_
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