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The K_max of the emitted photoelectron is related to the stopping potential V₀ by
A{'text': 'K_max = V₀/e', 'label': 'A'}
B{'text': 'K_max = 2eV₀', 'label': 'B'}
C{'text': 'K_max = e/V₀', 'label': 'C'}
D{'text': 'K_max = eV₀', 'label': 'D'}
Answer & Solution
Correct answer: D. {'text': 'K_max = eV₀', 'label': 'D'}
1. Photocurrent vanishes when the retarding potential exactly stops the fastest photoelectrons.
2. The energy needed to stop an electron of charge e across potential V₀ is eV₀.
3. Therefore K_max = eV₀ from energy conservation.
4. This is the standard formula relating stopping potential to maximum kinetic energy.
_Source: NCERT Class 12 Physics, Ch 11 "Dual Nature of Radiation and Matter", §11.4.2_
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