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The stopping potential V₀ at a given frequency of incident light is
A{'text': 'Directly proportional to the intensity', 'label': 'A'}
B{'text': 'Inversely proportional to intensity', 'label': 'B'}
C{'text': 'Independent of intensity', 'label': 'C'}
D{'text': 'Zero', 'label': 'D'}
Answer & Solution
Correct answer: C. {'text': 'Independent of intensity', 'label': 'C'}
1. Stopping potential corresponds to maximum kinetic energy of photoelectrons.
2. K_max = eV₀; K_max depends on frequency and metal, not on intensity.
3. Increasing intensity increases saturation current but not stopping potential.
4. So V₀ is independent of intensity at a given frequency.
_Source: NCERT Class 12 Physics, Ch 11 "Dual Nature of Radiation and Matter", §11.4.2_
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