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A coil of inductance 0.5 H carries a current changing at 4 A s⁻¹. The induced EMF is:
A0.5 V
B1 V
C2 V
D8 V
Answer & Solution
Correct answer: C. 2 V
1. |EMF| = L · |dI/dt| = 0.5 × 4 = 2 V.
2. The minus sign indicates back-EMF direction (opposes the change).
_Source: NCERT Class 12 Physics Ch 6 §6.8 (back-EMF numerical)_
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