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Motional EMF induced across a rod of length L moving with velocity v perpendicular to a field B is:
AEMF = B L v
BEMF = B L / v
CEMF = B v / L
DEMF = B / (L v)
Answer & Solution
Correct answer: A. EMF = B L v
1. dΦ/dt = B × (rate of area swept) = B × (L v).
2. So |EMF| = B L v.
3. Direction by Lenz's law.
_Source: NCERT Class 12 Physics Ch 6 §6.6 Motional EMF_
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