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Among HF, HCl, HBr and HI, the molecule with the highest dipole moment is:
AHF
BHCl
CHBr
DHI
Answer & Solution
Correct answer: A. HF
1. Dipole moment μ = δ × d. F has the highest electronegativity, giving the largest δ⁺/δ⁻ on H/F.
2. Although the bond length is shortest in HF, the very large electronegativity difference wins.
3. Observed dipole moments: HF 1.78 D > HCl 1.07 D > HBr 0.78 D > HI 0.38 D.
_Source: NCERT Class 11 Chem Ch 4 §4.2 Polar Covalent Bonds_
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