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A process whose enthalpy and entropy changes share the same arithmetic sign will show:
ATemperature-dependent spontaneity
BSpontaneity at all temperatures
CNonspontaneity at all points
DNo change in free energy
Answer & Solution
Correct answer: A. Temperature-dependent spontaneity
1. The signs of the two changes decide how temperature matters.
2. Enthalpy and entropy changes may be of the same arithmetic sign.
3. Such a process will exhibit a temperature-dependent spontaneity.
4. That behaviour is depicted by the two yellow lines in the plot.
5. When the signs differ, the verdict does not depend on temperature.
_Source: OpenStax Chemistry 2e (CC BY 4.0), Ch 16 'Thermodynamics', sections 16.1-16.4_
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