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The hybridisation of carbon in ethylene (C₂H₄) is:
Asp
Bsp²
Csp³
Dsp³d
Answer & Solution
Correct answer: B. sp²
1. Each C in ethylene forms three σ bonds (to two H and one C) and one π bond (to the other C).
2. Three σ bonds + no lone pairs ⇒ three hybrid orbitals are needed.
3. So hybridisation is sp² (trigonal planar around C, bond angle ~120°).
4. The double bond = 1 σ (sp²–sp²) + 1 π (unhybridised p–p).
_Source: NCERT Class 11 Chem Ch 4 §4.6 Hybridisation in Alkenes_
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