The number of radial nodes in a 3s orbital is:
A0
B1
C2
D3
Answer & Solution
Correct answer: C. 2
1. Total nodes = n − 1; angular nodes = ℓ; radial nodes = n − 1 − ℓ.
2. For 3s: n = 3, ℓ = 0, so radial nodes = 3 − 1 − 0 = 2.
3. Plus 0 angular nodes (s orbital is spherical).
_Source: syllabus Chem Ch 2 §2.6 (radial / angular nodes)_
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