The maximum number of electrons that can occupy the 4th principal shell (n = 4) is:
A16
B18
C32
D50
Answer & Solution
Correct answer: C. 32
1. Capacity of shell n = 2 n².
2. For n = 4: 2 × 16 = 32.
3. Breakdown: 4s² + 4p⁶ + 4d¹⁰ + 4f¹⁴ = 32.
_Source: syllabus Chem Ch 2 §2.6 Shell Capacity_
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