The energy of the n-th orbit in a hydrogen atom (Bohr) varies as:
AE_n ∝ n
BE_n ∝ n²
CE_n ∝ 1 / n²
DE_n ∝ 1 / n
Answer & Solution
Correct answer: C. E_n ∝ 1 / n²
1. Bohr derived E_n = −13.6 eV / n² for hydrogen.
2. Energy levels become more closely spaced for higher n.
3. Ionisation energy (n = 1 to ∞) is 13.6 eV.
_Source: NCERT Class 11 Chem Ch 2 §2.4 Bohr's Model_
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