The wavelength λ associated with a particle of momentum p (de Broglie hypothesis) is:
Aλ = h / p
Bλ = h p
Cλ = p / h
Dλ = h² / p
Answer & Solution
Correct answer: A. λ = h / p
1. de Broglie postulated wave–particle duality: every moving particle has an associated wave.
2. The wavelength is λ = h / p, where h is Planck's constant.
3. For an electron with kinetic energy K, p = √(2 m K), so λ = h / √(2 m K).
_Source: NCERT Class 11 Chem Ch 2 §2.6 Dual Behaviour of Matter_
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